

1. Choose the right fertilizer for your appetite
Generally speaking, fertilizing fruit trees is like eating, and a fertilizer is equivalent to a master chef. If a certain kind of fertilizer is too much or too little, the tree will appear "sub-health" state, such as weak or weak. In order to create a good site condition for root growth, the balanced fertilization of total nutrition should make efforts to supplement the organic matter, medium elements and trace elements which are seriously lacking in orchards. Because organic fertilizer is the "deposit book" of the soil, it plays an important role in the fertile soil root, improve the utilization rate of chemical fertilizer.
Chemical fertilizer should be formulated according to the different nutrient requirements of different varieties of fruit trees. Through a large number of field experiments, the reasonable ratios of nitrogen (n), phosphorus (P2O5) and potassium (K2O) of different fruit trees were determined as follows:
Apple 1:0.6:1
Grape 1:1.41:1.25
Pear 1:0.21:1.02
It should be emphasized here that although the annual growth and development of apple and pear have a "high medium high" demand for "nitrogen, phosphorus and potassium", the application of fertilizer in autumn should be more than 80% of the total amount of phosphorus fertilizer in the whole year, because autumn is the peak period of root growth in the whole year, phosphorus is the rooting nutrient, and the supply is stable throughout the year.
2. Fertilizer should be applied at "rice time"
The same kind of food, people feel comfortable when they eat it. When you miss a meal, it's tasteless. Autumn is the peak period of root growth of fruit trees. The nutrients absorbed and synthesized by roots are mainly used for storage, which plays an important role in germination, flowering, fruit setting and shoot growth in the coming year. Therefore, if the same fertilizer is applied from September to October, it will be as valuable as gold and silver; if it is applied after falling leaves and next spring, it will be devalued to the value of copper